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The statement ~(~prarrq) is equivalent t...

The statement `~(~prarrq)` is equivalent to (A) `pvv~q` (B) `~p^^q` (C) `~p^^~q` (D) `~pvvq`

A

`-(qv~p)rarrr`

B

`~rrarr(~pvq)`

C

`~((p^^(~q))^^(~r))`

D

`~rrarr(~p^^q)`

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The correct Answer is:
D
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