A particle moves along a constant curvature path between `A` and `B` (length of curve wire `AB` is `100m`) with a constant speed of `72km//hr`. The acceleration of particle at mid point `'C'` of curve `AB` is

Answer

B

Explanation

`a_(C)=(|bar(v)|^(2))/R=((20)^(2))/(400/(pi))=pim//s^(2)`