A uniform disc of mass m and radius `r` rolls without slipping along a horizontal surface and ramp, as shown above. The disk has an initial velocity of `upsilon` . What is the maximum height h to which the center of mass of the disc rises ?

Options

A. `h=(v^(2))/(2g)`
B. `h=(3v^(2))/(4g)`
C. `h=(v^(2))/g`
D. `h=(3v^(2))/(2g)`

Answer

B

Explanation

`3/4mv^(2)=mghimpliesh=(3v^(2))/(4g)`