Home
Class 12
PHYSICS
The dispersive power of the material of ...

The dispersive power of the material of a lens is `0.04` and the focal length of the lens is `10cm`. Find the difference in the focal length (in mm) of the lens for violet and red colour.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the difference in the focal lengths of the lens for violet and red colors based on the given dispersive power and the focal length of the lens. ### Step-by-Step Solution: 1. **Understanding Dispersive Power**: The dispersive power (ω) is given by the formula: \[ \omega = \frac{\mu_v - \mu_r}{\mu_{mean} - 1} \] where: - \(\mu_v\) is the refractive index for violet light, - \(\mu_r\) is the refractive index for red light, - \(\mu_{mean}\) is the mean refractive index. Given that the dispersive power is \(0.04\), we can use this value in our calculations. 2. **Using the Lens Maker's Formula**: The lens maker's formula relates the focal length \(f\) of a lens to its refractive index and radii of curvature: \[ \frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] For small changes in refractive index, we can differentiate this equation. 3. **Differentiating the Lens Maker's Formula**: We differentiate the lens maker's formula to find the change in focal length \(df\) with respect to the change in refractive index \(d\mu\): \[ df = \frac{d\mu}{(\mu - 1) \cdot \frac{1}{f^2}} \cdot \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] However, since we are interested in the difference in focal lengths for violet and red light, we will focus on the changes in refractive index. 4. **Calculating the Change in Focal Length**: We know that: \[ df = -10 \cdot \frac{(\mu_v - \mu_r)}{(\mu - 1)} \] Substituting the dispersive power: \[ df = -10 \cdot \frac{0.04}{1} = -0.4 \text{ cm} \] 5. **Converting to mm**: Since we need the answer in mm, we convert: \[ df = -0.4 \text{ cm} \times 10 = -4 \text{ mm} \] The negative sign indicates a difference, but we are interested in the magnitude: \[ \text{Difference in focal length} = 4 \text{ mm} \] ### Final Answer: The difference in the focal length of the lens for violet and red color is **4 mm**.

To solve the problem, we need to find the difference in the focal lengths of the lens for violet and red colors based on the given dispersive power and the focal length of the lens. ### Step-by-Step Solution: 1. **Understanding Dispersive Power**: The dispersive power (ω) is given by the formula: \[ \omega = \frac{\mu_v - \mu_r}{\mu_{mean} - 1} ...
Promotional Banner

Topper's Solved these Questions

  • TEST PAPERS

    RESONANCE ENGLISH|Exercise PART - II PHYSICS|106 Videos
  • SIMPLE HARMONIC MOTION

    RESONANCE ENGLISH|Exercise Advanced Level Problems|13 Videos
  • TEST SERIES

    RESONANCE ENGLISH|Exercise PHYSICS|130 Videos

Similar Questions

Explore conceptually related problems

Find the focal length of the lens shown in Fig.

Find the focal length of the lens shown in the Fig..

The power of a lens is -5 D. Find its focal length.

If the focal length of the lens is 20 cm, find the distance of the image from the lens in the following figure?

A focal length of a lens 10cm. What is power of a lens in dipotre?

If the focal length of objective lens is increased then magnifying power of

Find the power of a concave lens of focal length 2 m .

If the focal length of the objective lens is increased then Magnifying power

The focal length of a plano-concave lens is -10 cm , then its focal length when its palne surface is polished is

RESONANCE ENGLISH-TEST PAPERS-PHYSICS
  1. If the distance between two images formed by upper and lower part of t...

    Text Solution

    |

  2. The minimum magnifying power of a telescope is M. If focal length of i...

    Text Solution

    |

  3. The dispersive power of the material of a lens is 0.04 and the focal l...

    Text Solution

    |

  4. A thin prism of glass is placed in air and water respectively. If n(0)...

    Text Solution

    |

  5. A fiber of length 10cm is illuminated with light from an light emittin...

    Text Solution

    |

  6. Figure shows two coherent sources S(1) and S(2) vibrating in same phas...

    Text Solution

    |

  7. In Young's Double slit experiment, a thin glass mica strip of thicknes...

    Text Solution

    |

  8. In young's double-slit experiment, the slit are 2 mm apart and are ill...

    Text Solution

    |

  9. A thin oil film of refractive index 1.2 floats on the surface of water...

    Text Solution

    |

  10. Radiowaves of wavelength 3m are incident on a rectangular hole of widt...

    Text Solution

    |

  11. In the figure shown, the maximum number of reflections will be:

    Text Solution

    |

  12. In the fraunhaufer differaction from a single slit illuminated by poly...

    Text Solution

    |

  13. Assuming the earth to be a homogeneous sphere of radius R, its density...

    Text Solution

    |

  14. An isolated triple star systerm consists of two identical stars, each ...

    Text Solution

    |

  15. A uniform thin rod of mass m and length R is placed normally on surfac...

    Text Solution

    |

  16. Two artificial satellites of the same mass are moving around the earth...

    Text Solution

    |

  17. A planet is revolving in an elliptical orbit around the sun as shown i...

    Text Solution

    |

  18. Suppose the earth suddenly shrinks in size, still remaining spherical ...

    Text Solution

    |

  19. Maximum height reached by a rocket fired with a speed equal to 50% of...

    Text Solution

    |

  20. A soap bubble (surface tension=T) is charged to maximum surface densit...

    Text Solution

    |