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lim(nrarroo)(1/(n+1)+1/(n+2)+…….+1/(6n))...

`lim_(nrarroo)(1/(n+1)+1/(n+2)+…….+1/(6n))=kln6`, then find the value of `k`

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The correct Answer is:
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`lim_(nrarroo)(1/(n+1)+1/(n+2)+…+1/(6n))`
`=lim_(nrarroo)sum_(r=1)^(5n)1/(n+r)=lim_(rarroo)sum_(r=1)^(5n)1/n. 1/((1+r/n))=int_(0)^(5)1/(1+x)dx`
`=[ln(1+x)]_(0)^(5)=ln6=ln1=ln6`
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