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Flux (ph) as a function of distance (r) ...

Flux `(ph)` as a function of distance `(r)` from centre of uniformly charged solid sphere of charge `Q` and radius `R`, is best represented by

A

B

C

D

(D)

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To find the relationship between the electric flux (Φ) and the distance (r) from the center of a uniformly charged solid sphere of charge Q and radius R, we can use Gauss's Law. Let's go through the solution step by step: ### Step 1: Understanding Gauss's Law Gauss's Law states that the electric flux through a closed surface is equal to the charge enclosed (Q_enc) divided by the permittivity of free space (ε₀): \[ \Phi = \frac{Q_{\text{enc}}}{\epsilon_0} \] ### Step 2: Case 1 - Inside the Sphere (r < R) When we are inside the sphere (r < R), we need to find the charge enclosed (Q_enc) within a Gaussian surface of radius r. 1. The charge density (ρ) of the sphere can be calculated as: \[ \rho = \frac{Q}{\frac{4}{3}\pi R^3} \] 2. The volume of the Gaussian surface of radius r is: \[ V = \frac{4}{3}\pi r^3 \] 3. The charge enclosed (Q_enc) within this Gaussian surface is: \[ Q_{\text{enc}} = \rho \cdot V = \left(\frac{Q}{\frac{4}{3}\pi R^3}\right) \cdot \left(\frac{4}{3}\pi r^3\right) = Q \cdot \frac{r^3}{R^3} \] 4. Now, substituting Q_enc into Gauss's Law: \[ \Phi = \frac{Q \cdot \frac{r^3}{R^3}}{\epsilon_0} = \frac{Q}{\epsilon_0} \cdot \frac{r^3}{R^3} \] This shows that the flux (Φ) is proportional to \(r^3\) when \(r < R\). ### Step 3: Case 2 - Outside the Sphere (r ≥ R) When we are outside the sphere (r ≥ R), the entire charge Q is enclosed within the Gaussian surface. 1. The charge enclosed is simply Q. 2. Applying Gauss's Law: \[ \Phi = \frac{Q}{\epsilon_0} \] This indicates that the flux (Φ) is constant and does not depend on r when \(r \geq R\). ### Step 4: Summary of Results - For \(r < R\): \(\Phi \propto r^3\) - For \(r \geq R\): \(\Phi = \frac{Q}{\epsilon_0}\) (constant) ### Conclusion The relationship between the electric flux and the distance from the center of the uniformly charged solid sphere is best represented by a graph that shows: - A cubic relationship for \(r < R\) (increases as \(r^3\)) - A constant value for \(r \geq R\) Thus, the correct option is **C**. ---

To find the relationship between the electric flux (Φ) and the distance (r) from the center of a uniformly charged solid sphere of charge Q and radius R, we can use Gauss's Law. Let's go through the solution step by step: ### Step 1: Understanding Gauss's Law Gauss's Law states that the electric flux through a closed surface is equal to the charge enclosed (Q_enc) divided by the permittivity of free space (ε₀): \[ \Phi = \frac{Q_{\text{enc}}}{\epsilon_0} \] ...
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