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A point charge Q is kept at point 'A' th...

A point charge `Q` is kept at point `'A'` the flux through the inclined surface of cone is `(3Q)/(5epsilon_(0))`. Now another charge `-Q` is also placed at point `B`. If net flux through the inclined surface `(nQ)/(5epsilon_(0))` is Find `n`.

Text Solution

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The correct Answer is:
1
`(nQ)/(5epsilon_(0))=(3Q)/(5epsilon_(0))-[Q/(epsilon_(0))-(3Q)/(5epsilon_(0))]=Q/(5epsilon_(0))`
`n=1`
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