Two measure diameter of a wire a screw-gauge is used The main scale division is of `1mm` In a complete rotation the screw advances by `1mm` and the circular scale has 100 divisions The reading of screw-gauge is as shown in If there is no error is no error in mass measurement but error in length measurement is `1%` then find max Possible error in density if diameter is 3.07 mm.

Explanation

To solve the problem, we need to find the maximum possible error in density given the diameter of the wire and the percentage error in length measurement.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Diameter of the wire, \( D = 3.07 \, \text{mm} \)
- Percentage error in length measurement, \( \frac{\Delta L}{L} \times 100 = 1\% \)
- Main scale division (MSD) = \( 1 \, \text{mm} \)
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