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A vernier has 10 divisions and they are ...

A vernier has 10 divisions and they are equal to 9 divisions of main scale in length. If the main scale is calibrated in mm, what is its least count?

Text Solution

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From first Excess reading (zero error) = 0.6mm If an object is placed vernier gives `14,6mm` in which there is `0.6mm` excess reading which has to be subtracted So actual thickness `= 14.6 - 0.6 = 14.0 mm` we can also do it using the formula
`=14.6 - 0.6 = 14.0mm`
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