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In electrical calorimeter experiment, vo...

In electrical calorimeter experiment, voltage across the heater is `100.0 V` and current is `10.0 A`. Heater is switched on for t `= 700.0 s`. Room temperature is `theta_0 = 10.0^(@)C` and final temperature of calorimeter and unknown liquid is `theta_f = 73.0^(@) C`. Mass of empty calorimeter is `m_1 = 1.0kg` and combined mass of calorimeter and unknown liquid is `m_2 = 3.0 kg`. Find the specificheat capacity of the unknown liquid in proper significant figures. Specific heat of calorimerter = `3.0xx10^3 j//kg .^(@) C`.

Text Solution

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corrected final temperature `= theta_(f) = 73.0^(@) + 7.0^(@) = 80.0^(@)`
`S=(((100.0)(10.0)(700.0))/(80.0-10.00)(1.0)(3.0xx10^(3)))/(3.0-1.0)`
`=3.5 xx 10^(3)J//kg^(@)C` (According to addition and muktiplication rule of `S.F` ) .
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