Force between two charges when placed in free space is 10N. If they are in a medium of relative permittivity 5, the force between them will be

Options

A. 2N
B. 50N
C. 0.5N
D. None of these

Explanation

To solve the problem of finding the force between two charges when placed in a medium with a relative permittivity of 5, we can follow these steps:

### Step 1: Understand the relationship between force in free space and in a medium
According to Coulomb's law, the force \( F \) between two charges \( Q_1 \) and \( Q_2 \) in free space (or vacuum) is given by:
\[ F_{\text{air}} = \frac{1}{4 \pi \epsilon_0} \frac{Q_1 Q_2}{R^2} \]
where \( \epsilon_0 \) is the permittivity of free space.
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