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To estimate g (from g = 4 pi^(2)(L)/(T^(...

To estimate `g` (from `g = 4 pi^(2)(L)/(T^(2))`), error in measurement of `L` is `+- 2%` and error in measurement of `Tis +- 3%` The error in estimated `g` will be

A

`+-8%`

B

`+-6%`

C

`+-3%`

D

`+-5%`

Text Solution

AI Generated Solution

To estimate the gravitational acceleration \( g \) using the formula \( g = \frac{4 \pi^2 L}{T^2} \), we need to calculate the percentage error in \( g \) based on the given percentage errors in \( L \) and \( T \). ### Step-by-Step Solution: 1. **Identify the given errors**: - The error in measurement of length \( L \) is \( \pm 2\% \). - The error in measurement of time \( T \) is \( \pm 3\% \). ...
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