A student performs an experiment for determination of `g(=(4pi^(2)l)/(T^(2))),~~1m`, and he commits an error of `Deltal`.
For `T` he takes the time of `n` oscillations with the stop watch of least count `Delta` and he commits is human error of `0.1sec`. For which of the following data, the measurement of `g` will be most accurate?

Options

A. `DeltaL =0.5,DeltaT =0.1, n =20`
B. `DeltaL =0.5, DeltaT =0.1, n =50`
C. `DeltaL = 0.5 DeltaT = 0.01, n = 20`
D. `DeltaL = 0.1DeltaT = 0.05, n=50`

Explanation

`(Deltag)/(g) = (DeltaL)/(L) + 2(DeltaT)/(T)`
In option `(D)` error in `Deltag` is minimum and number of repetition of measurement are maximum In this case the error in g is minimum .