A meter bridge is set- up as shown in figure, to determine an unknown resistance `X` using a standard ` 10 Omega` resistor. The galvanometer shows null point when tapping - key is at `52 cm` mark. The end -corrections are `1 cm` and `2 cm` respectively for the ends `A` and `B`. The determined values of `X` is .

(a) `10.2 Omega`
(b) `10.6 Omega`
(c) `10.8 Omega`
(d) `11.1 Omega`.

Options

A. `10.2ohm`
B. `10.6ohm`
C. `10.8ohm`
D. `11.1ohm`

Explanation

`l_(1) = 52 + 1 = 53 cm`
`l_(2) = 48 + 2 = 50 cm`
`(l_(1))/(l_(2)) = (x)/(R) rArr (53)/(50) = (x)/(10)`
`x = 10.6 Omega` .