A particle having a charge of `5.0 mu C` and a mass of `5.0 X 10^(-12)kg` is projected with a speed of `1.0km s^(-1)` in a magnetic field of a magnetic field of magnitude 5.0 m T. The angle between the magnetic field and the velocity is `sin^(-1)(0.90)`. show that the path of the particle will be a helix. Find the diameter of the helix and its pitch.

Answer

A, C, D

Explanation

`r=(mV_(bot))/(qB)`
`=(5xx10^(-12)xx1xx10^(3)xx0.9)/(5xx10^(-6)xx5xx10^(-3))=18cm`
Diameter `=36cm`
`T=(2pim)/(qB)`
`P=V cos thetaxx(2pim)/(qB)`
`=4pisqrt19 cm`