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A charge Q is spread uniformly over an i...

A charge Q is spread uniformly over an insulated ring of radius R. What is the magnetic moment of the ring if it is rotated with and angular velocity w with respect to the normal axis ?

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The correct Answer is:
A, B
`i=Qf=(Qomega)/(2pi)`
`M=ixxpiR^(2)=(QomegaR^(2))/2`
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