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A circular coil of radius R and a curren...

A circular coil of radius R and a current `I`, which can rotate about a fixed axis passing through its diameter is initially placed such that its plane lies along magnetic field B, kinetic energy of loop when it rotates through an angle `90^(@)` is : (Assume that `I` remains constant)

A

`piR^(2)BI`

B

`piR^(2)BI/2`

C

`2piR^(2)BI`

D

`3/2piR^(2)I`

Text Solution

Verified by Experts

The correct Answer is:
A
Loss in potential energy = gain in kinetic energy
`(-MB cos 90^(@))-(-MB cos 0^(@))=KE`
`= MB=KE`
`piR^(2)IB=KE`
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