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A uniform rod of length `L` and mass `M` is hinged at its upper point and is at rest at that moment in the vertical plane.A current `i` flows in it.A uniform magnetic field of strength `B` exists perpendicular to the rod and in horizontal direction. The force exerted by the hinge on the rod just after release in horizontal direction is `(iLB)/N`.Then find the value of `N`.

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