Figure shows (only cross section) a wooden cylinder `C` with a mass `m` of `0.25 kg`,a radius `R` and a length `l` perpenducular to the plane of paper of `0.1 meter` with `N=10` where `N` is number of turns of wire loop contains the axis of the cylinder the least current through the loop is `P/2A` that will prevent the cylinder from moving down a plane whose surface is inclined at angle `theta` to the horizontal, in the presence of a vertical field of magnetic induction `0.5 weber//meter^(2)`, if the planer of the windings is parallel to the inclinded plane?(bottom most point of cylinder does not slip)then find value of `P`.

Explanation

`M=Lxx2Rxxi`
`MB sin theta=mg sintheta R`
`i=(mg)/(2BNI)`
`=2.5A`