Home
Class 12
PHYSICS
The magnetic field at the origin due to ...

The magnetic field at the origin due to a current element I `(vec dl ) placed at a positon (vec r) is`

A

`(mu_(0)i)/(4pi)(dveclxxvecr)/r^(3)`

B

`-(mu_(0)i)/(4pi)(rxxvecr)/r^(3)`

C

`(mu_(0)i)/(4pi)(dveclxxvecr)/r^(3)`

D

`-(mu_(0)i)/(4pi)(dveclxxvecr)/r^(1)`

Text Solution

Verified by Experts

The correct Answer is:
C, D
Promotional Banner

Topper's Solved these Questions

  • ELECTRODYNAMICS

    RESONANCE ENGLISH|Exercise Exercise-2 PART-3 COMPREHENSION-1|5 Videos

  • ELECTRODYNAMICS

    RESONANCE ENGLISH|Exercise Exercise-2 PART-3 COMPREHENSION-2|3 Videos

  • ELECTRODYNAMICS

    RESONANCE ENGLISH|Exercise Exercise-2 PART-2|26 Videos

  • ELECTRO MAGNETIC WAVES

    RESONANCE ENGLISH|Exercise Exercise 3|27 Videos

  • ELECTROMAGNETIC INDUCTION

    RESONANCE ENGLISH|Exercise A.l.P|19 Videos

Similar Questions

Explore conceptually related problems

The magnetic field at the origin due to a current element I vec(dl) placed at position r is (i) ((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3))) -((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3))) (iii) ((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3))) -((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3)))

The magnetic field at the origin due to the current flowing in the wire is

The magnetic field at the origin due to the current flowing in the wire is

Find the field at the origin O due to the current i=2A .

The magnetic field bar(dB) due to a small current element bar(dl) at a distance vec(r) and carrying current 'I' is

Find the magnetic field at the ccentre of a current carrying conductor bent in the form of an arc subtending angle theta at its centre. Radius of the arc is R Strategy: Let the arc lie in x-y plane with its centre at the origin. Consider a small current element i vec(dl) as shown. The field due to this element at the centre can be obtained by Biot-Savart law

What is the magnetic field |vec(B)| at the point P due to a current carrying wire of length AB (having a current of 2A) shown in figure ?

A: In any magnetic field region the line integral ointvecB.vec(dl) along a closed loop is always zero. R: The magnetic field vecB in the expressioin oint vecB.vec(dl) is due to the currents enclosed only by the loop.

The electric field intensity vec(E) , , due to an electric dipole of dipole moment vec(p) , at a point on the equatorial line is :

Use Biot-Savart law to derive the expression for the magnetic field on the axis of a current carrying circular loop of radius R . Draw the magnetic field lines due to circular wire carrying current I .

RESONANCE ENGLISH-ELECTRODYNAMICS-Exercise-2 PART-3
  1. A magnetic needls is kept in a non-unifrom magnetic field . It exper...

    Text Solution

    |

  2. The magnetic field at the origin due to a current element I (vec dl ) ...

    Text Solution

    |

  3. A non-conducting disc having unifrom positive charge Q, is rotating ab...

    Text Solution

    |

  4. A hollow tube is carrying an electric current along its length distrib...

    Text Solution

    |

  5. In a coaxial, straight cable, the central conductor and the outer cond...

    Text Solution

    |

  6. A particle of charge +q and mass m moving under the influence of unifo...

    Text Solution

    |

  7. Let vecE and vecB denote the electric and magnetic field in a certain ...

    Text Solution

    |

  8. Magnetic field strength at the centre of regular pentagon made of a co...

    Text Solution

    |

  9. H^(+), He^(+) and O^(2+) ions having same kinetic energy pass through ...

    Text Solution

    |

  10. A beam of electrons moving with a momentum p enters a uniform magnetic...

    Text Solution

    |

  11. Two ions have equal masses but one is singly- ionized and the other i...

    Text Solution

    |

  12. If a charged particle at rest experiences no electromagnetic force,

    Text Solution

    |

  13. A charged particle goes undeflected in a region containing electric a...

    Text Solution

    |

  14. A charged particle moves along a circle under the action of possible c...

    Text Solution

    |

  15. A single circular loop of wire radius 0.02 m carries a current of 8.0 ...

    Text Solution

    |

  16. Figure shows cross-section of two large parallel metal sheets carrying...

    Text Solution

    |

  17. Let [epsilon(0)] denote the dimensional formula of the permittivity of...

    Text Solution

    |

  18. An electron is moving along the positive x-axis. You want to apply a m...

    Text Solution

    |