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Equal volume of 0.2M NH(4)OH (or ammonia...

Equal volume of `0.2M NH_(4)OH` (or ammonia) are `0.1MH_(2)SO_(4)` are mixed.Calculated pH of final solution.Given :`K_(b)` of `NH_(3)=1.8xx10^(-5)` at `25^(@)C`.

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To solve the problem of finding the pH of the final solution when equal volumes of 0.2 M NH₄OH (ammonia) and 0.1 M H₂SO₄ are mixed, we can follow these steps: ### Step 1: Determine the concentrations after mixing Since equal volumes of the two solutions are mixed, the concentrations of both solutions will be halved. - Initial concentration of NH₄OH = 0.2 M - Concentration after mixing = 0.2 M / 2 = 0.1 M ...
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