pH = 7.4 , `K_1` of `H_2CO_3` = 4.5 X `10^(-7)` . What will be the ratio of `[HCO_3^-]` to `[H_2CO_3]`

Acid rain takes place dur to combination of acidic oxides with water and it is an environmental concern all over the world. Assuming rain water is uncontaminated with HNO_(3) or H_(2)SO_(4) and is in equilibrium with 1.25 xx 10^(-4) atm CO_(2) . The Henry's law constant (K_(H)) is 1.25 xx 10^(6) "torr". K_(a_(1)) of H_(2)CO_(3) = 4.3 xx 10^(-7) What is the pH of neutral rain water ?

When solid SrCO_(3) is equilibrated with a pH 8.60 buffer, the solution was found to have [Sr^(2+)] = 2.2 xx 10^(-4) . What is the K_(sp) of SrCO_(3) . (K_(2) of H_(2)CO_(3) = 4.7 xx 10^(-11))

Na_(2)B_(4)O_(7) + X to H_(3) BO_(3) . What is X in the reaction

A : For H_2CO_3 K_(a_1) lt K_(a_2) . R : H_2CO_3 is weaker acid than HCO_3^-

The pH of blood is 7.4 . What is the ratio of [(HPO_(4)^(2-))/(H_(2)PO_(4)^(-))] in the blood. pK_(a)(H_(2)PO_(4)^(-))=7.1

What % of the carbon in the H_(2)CO_(3)-HCO_(3)^(-) buffer should be in the form of HCO_(3)^(-) so as to have a neutral solution? (K_(a)=4xx10^(-7))

Carbonic acid (H_(2)CO_(3)), a diprotic acid has K_(a1)=4.0xx10^(-7) and K_(a2)=7.0xx10^(-11). What is the [HCO_(3)^(-)] of a 0.025 M solution of carbonic acid?

Citric acid (H_(3)A) is a polyprotic acid with K_(1),K_(2) , and K_(3) equals to 7.4 xx 10^(-4), 1.7 xx 10^(-5) , and 4.0 xx 10^(-7) , respectively. Calculate the [H^(o+)], [H_(2)A^(Theta)], [HA^(2-)] , and [A^(3-)] in 0.01M citric acid.

Carbonic acid (H_(2)CO_(3)), a diprotic acid has K_(a1)=4.0xx10^(-7) and K_(a2)=7.0xx10^(-11). What is the [CO_(3)^(2-)] of a 0.025 M solution of carbonic acid?

Choose the right sequential phenomena among following during the delivery of O_(2) from blood to tissue P. Absorption of CO_(2) by the blood Q. Reaction of absorbed CO_(2) " with " H_(2)O to from H_(2)CO_(3) within RBC and its conversion into H^(+) and HCO_(3)^(-) ions R. Reaction of absorbed CO_(2) " with " H_(2)O in plasma to form H_(2)CO_(3) and its conversion into H^(+) " and " HCO_(3)^(-) S. Combination of H^(+) with haem portion of HbO_(2) to release O_(2) T. Comnbination of HCO_(3)^(-) with haem portion HbO_(2) to form reduced haemoglobin and release of O_(2)