Write balanced equations for the following reactions:
Tin is treated with an excess of chlorine gas.

Answer

To write the balanced equation for the reaction of tin with excess chlorine gas, we can follow these steps:

### Step 1: Identify the Reactants and Products
- **Reactants**: Tin (Sn) and Chlorine gas (Cl₂).
- **Product**: Stannic chloride (SnCl₄).

### Step 2: Write the Unbalanced Equation
The unbalanced equation for the reaction can be written as:
\[ \text{Sn} + \text{Cl}_2 \rightarrow \text{SnCl}_4 \]

### Step 3: Balance the Equation
Now, we need to balance the equation.
- On the left side, we have 1 Sn and 2 Cl (from Cl₂).
- On the right side, we have 1 Sn and 4 Cl (from SnCl₄).

To balance the chlorine atoms, we need to adjust the coefficients:
- We can place a coefficient of 2 in front of SnCl₄ to balance the chlorine atoms:
\[ \text{Sn} + 2\text{Cl}_2 \rightarrow \text{SnCl}_4 \]

Now, we have:
- Left side: 1 Sn and 4 Cl (2 Cl₂ gives 4 Cl).
- Right side: 1 Sn and 4 Cl (from SnCl₄).

### Final Balanced Equation
The balanced equation for the reaction of tin with excess chlorine gas is:
\[ \text{Sn} + 2\text{Cl}_2 \rightarrow \text{SnCl}_4 \]