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Given the order of density: DiamondgtG...

Given the order of density:
Diamond`gt`Graphite`gt`Fullerence `C_(60)`, choose thye correct order for `C-C` bond length (Consider large bond length if there are two different bondlengths)

A

Diamond `lt` graphite`lt` fullerene `(C_(60))`

B

Diamond `gt` graphite`gt` fullerene `(C_(60))`

C

Diamond `gt` fullerene `(C_(90^(@))) gt`graphite

D

Diamond `lt` fullerene `(C_(90^(@))) lt`graphite

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of C-C bond lengths in diamond, graphite, and fullerene (C60), we need to analyze the hybridization and structure of each form of carbon. ### Step-by-Step Solution: 1. **Identify the Hybridization in Each Structure:** - **Diamond:** In diamond, each carbon atom is sp³ hybridized. This means that each carbon forms four single bonds with other carbon atoms in a tetrahedral structure. - **Graphite:** In graphite, each carbon atom is sp² hybridized. This allows each carbon to form three sigma bonds and one delocalized pi bond, resulting in a planar structure. - **Fullerene (C60):** In C60, the carbon atoms are arranged in a structure that resembles a soccer ball. The hybridization is a mix of sp² and sp³, leading to different bond lengths. 2. **Determine the Bond Lengths:** - **Diamond:** The C-C bond length in diamond is approximately 154 picometers (pm). - **Graphite:** The C-C bond length in graphite is around 141.5 pm. - **Fullerene (C60):** Fullerene has two types of bond lengths due to its structure: approximately 138 pm and 143 pm. 3. **Compare the Bond Lengths:** - From the above information, we can summarize the bond lengths: - Diamond: 154 pm - Graphite: 141.5 pm - Fullerene (C60): 138 pm and 143 pm 4. **Establish the Order of C-C Bond Lengths:** - Since we need to consider the larger bond length when there are two different bond lengths in fullerene, we will take the larger bond length of C60 (143 pm). - Therefore, the order of C-C bond lengths from longest to shortest is: - Diamond (154 pm) > Fullerene (143 pm) > Graphite (141.5 pm) ### Final Order: **C-C Bond Lengths: Diamond > Fullerene (C60) > Graphite**

To determine the correct order of C-C bond lengths in diamond, graphite, and fullerene (C60), we need to analyze the hybridization and structure of each form of carbon. ### Step-by-Step Solution: 1. **Identify the Hybridization in Each Structure:** - **Diamond:** In diamond, each carbon atom is sp³ hybridized. This means that each carbon forms four single bonds with other carbon atoms in a tetrahedral structure. - **Graphite:** In graphite, each carbon atom is sp² hybridized. This allows each carbon to form three sigma bonds and one delocalized pi bond, resulting in a planar structure. - **Fullerene (C60):** In C60, the carbon atoms are arranged in a structure that resembles a soccer ball. The hybridization is a mix of sp² and sp³, leading to different bond lengths. ...
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RESONANCE ENGLISH-P-BLOCK ELEMENT (BORON AND CARBON FAMILY)-Exercise-2 Part-I : ONLY ONE OPTION CORRECT TYPE
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  2. Given the order of density: DiamondgtGraphitegtFullerence C(60), cho...

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  4. Isolation of boron in very high purity is extremely difficult because ...

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  5. Reaction I : 3C ( natural graphite) + SiO(2)overset("heat")tounderset(...

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  6. True statement is:

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  7. Identify true statement:

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  8. An element E = (B,C,Si,Ge), predict E on the basic of given conditions...

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  9. In limited supply of oxygen C & Si are allowed to react at sufficientl...

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  12. Select the incorrect statement of the following.

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  13. Which of the following statements is correct for diborane?

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  15. Borazine and benzene show striking similarities in their properties. T...

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  16. Aqueous ammonia is used as a precipitating reagent for Al^(3+) ions as...

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  17. Borax is used as buffer since :

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  18. Which of the following sompound is obtained on heating potassium ferro...

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  19. B(OH)(3)+NaOH to Na[B(OH)(4)](aq). Then addition of which of the fo...

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