`SnCl_(4)` stannic chloride hydrolyses in dilute solution as per given reaction `SnCl_(4)+4H_(2)Oto[Sn(OH)_(4)]+4HCl`. Hydrolysis can be repressed by adding compound `"A"`.`SnCl_(4)+A to B, B` can be:

Options

A. `Sn(OH)_(4)`
B. `SnCl_(2)`
C. `H_(2)SnCl_(6)`
D. `Sn(OH)Cl`

Answer

To solve the question regarding the hydrolysis of stannic chloride (SnCl₄) and the addition of compound "A" that represses this hydrolysis, we can follow these steps:

### Step 1: Understand the Hydrolysis Reaction
The hydrolysis of stannic chloride is represented by the reaction:
\[ \text{SnCl}_4 + 4 \text{H}_2\text{O} \rightarrow \text{Sn(OH)}_4 + 4 \text{HCl} \]
This indicates that stannic chloride reacts with water to form stannic hydroxide and hydrochloric acid.

**Hint:** Recognize the products formed during hydrolysis to understand the reaction's context.

### Step 2: Identify the Role of Compound "A"
The question states that the hydrolysis can be repressed by adding a compound "A". This means that "A" should be a compound that can interact with SnCl₄ in a way that prevents its reaction with water.

**Hint:** Consider compounds that can form stable complexes with SnCl₄ or alter its reactivity.

### Step 3: Analyze Possible Compounds for "A"
We need to determine what "B" could be when SnCl₄ reacts with "A". The options provided include:
1. Stannic hydroxide (Sn(OH)₄)
2. Stannous chloride (SnCl₂)
3. H₂SnCl₆ (a complex)
4. SnOHCl

Among these, we should focus on the complex formation that can occur when SnCl₄ interacts with "A".

**Hint:** Look for compounds that are known to form stable complexes with metal chlorides.

### Step 4: Determine the Correct Compound "A"
The addition of a Lewis base or a ligand can help in forming a complex, thus preventing hydrolysis. One such compound that can form a complex with SnCl₄ is H₂SnCl₆ (tin(IV) chloride complex).

Thus, the reaction can be represented as:
\[ \text{SnCl}_4 + \text{A} \rightarrow \text{H}_2\text{SnCl}_6 \]
where "A" is a suitable ligand or base that stabilizes the stannic chloride.

**Hint:** Identify the nature of "A" based on its ability to form complexes with SnCl₄.

### Conclusion
The compound "B" formed when SnCl₄ reacts with "A" is:
\[ B = \text{H}_2\text{SnCl}_6 \]

### Final Answer
The answer is **H₂SnCl₆**.