`BF_(3)` on hydrolysis forms

Options

A. `H_(3)BO_(3)`
B. `HBF_(4)`
C. both (A) and (B)
D. none of these

Explanation

To determine the products of the hydrolysis of BF₃ (Boron Trifluoride), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant in this reaction is BF₃ (Boron Trifluoride) and water (H₂O).

2. **Write the Hydrolysis Reaction**:
- When BF₃ reacts with water, the chemical reaction can be represented as:
\[ BF_3 + H_2O \rightarrow H_3BO_3 + H^+ + BF_4^- \]

3. **Identify the Products**:
- The products of the hydrolysis reaction are:
- **H₃BO₃** (Boric Acid)
- **HBF₄** (Tetrafluoroborate Ion)

4. **Conclusion**:
- Therefore, the hydrolysis of BF₃ produces both H₃BO₃ and HBF₄.

5. **Select the Correct Option**:
- Since both products (H₃BO₃ and HBF₄) are formed, the correct answer is that both A (H₃BO₃) and B (HBF₄) are produced.

### Final Answer:
The hydrolysis of BF₃ forms both H₃BO₃ (Boric Acid) and HBF₄ (Tetrafluoroborate Ion).