Home
Class 12
CHEMISTRY
Three moles of B(2)H(6) are completely...

Three moles of `B_(2)H_(6)` are completely reacted with methanol. The number of moles of boron containing products formed is ________.

Text Solution

Verified by Experts

`B_(2)H_(6)+6CH_(3)OHto2B(OCH_(3))_(3)+6H_(2)`
For `3` moles of `B_(2)H_(6)` mole of `B` containing product formed =`6`
Promotional Banner

Topper's Solved these Questions

  • P-BLOCK ELEMENT (BORON AND CARBON FAMILY)

    RESONANCE ENGLISH|Exercise Exercise-3 Part-II : JEE (MAIN) / AIEE PROBLEMS (PREVIOUS YEARS)|12 Videos
  • P-BLOCK ELEMENT (BORON AND CARBON FAMILY)

    RESONANCE ENGLISH|Exercise Advanced Level Problems Part-I : PRACTICE TEST-1 (IIT-JEE (MAIN Pattern))|28 Videos
  • P-BLOCK ELEMENT (BORON AND CARBON FAMILY)

    RESONANCE ENGLISH|Exercise Exercise-2 Part-IV : COMPREHENSIONS|11 Videos
  • P BLOCK ELEMENTS

    RESONANCE ENGLISH|Exercise PART -II|23 Videos
  • P-BLOCK ELEMENTS (HALOGEN & NOBLE GASES)

    RESONANCE ENGLISH|Exercise APSP PART-3|22 Videos

Similar Questions

Explore conceptually related problems

Three moles of B_(2)H_(6) are completely reacted with methanol. The number of moles of boron containing product formed is.

The number of moles of Methanol in 480 g is

B_(2)H_(6) on reaction with methanol does not form

The number of moles of H_(2)O_(2) required to completely react with 400 ml of 0.5 N KMnO_(4) in acidic medium are

How many moles of CH_(3)OH required to react completely with (B) ?

In three moles of ethane (C_(2)H_(6)) , calculate the following: (i) Number of moles of carbon atoms. (ii) Number of moles of hydrogen atoms. (iii) Number of molecules of ethane.

0.5 mole of H_(2)SO_(4) is mixed with 0.2 mole of Ca(OH)_(2) . The maximum number of mole of CaSO_(4) formed is:

In one mole of ethane (C_(2)H_(6)) , calculate the following: a. Number of moles of carbon atoms b. Number of moles of hydrogen stoms c. Number of molecules of ethane.

1- Methylcyclohexene is allowed to react with B_(2)H_(6) . The product is then treated with H_(2)O_(2) and NaOH . The reaction is - The product formed is

One mole of H_(2) and 2 moles of I_(2) are taken initially in a two litre vessel. The number of moles of H_(2) at equilibrium is 0.2. Then the number of moles of I_(2) and HI at equilibrium is