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When a mixture of air and steam is passe...

When a mixture of air and steam is passed over red hot coke, the outgoing gas is:

A

Producer gas

B

Water gas

C

Coal gas

D

None of these

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The correct Answer is:
To solve the question, we need to analyze the reaction that occurs when a mixture of air and steam is passed over red hot coke. Here are the steps to derive the answer: ### Step 1: Understand the Components - **Coke** is primarily carbon (C) and is used as a reducing agent in various chemical reactions. - **Air** contains oxygen (O2) and nitrogen (N2). - **Steam** is water in the form of vapor (H2O). ### Step 2: Identify the Reaction When red hot coke reacts with air (specifically the oxygen in the air) and steam, two main reactions can occur: 1. The reaction of carbon with oxygen from air to produce carbon monoxide (CO). 2. The reaction of carbon with steam to produce carbon monoxide (CO) and hydrogen gas (H2). ### Step 3: Write the Chemical Equations 1. **C + O2 → 2CO** (Carbon reacts with oxygen to form carbon monoxide) 2. **C + H2O → CO + H2** (Carbon reacts with steam to form carbon monoxide and hydrogen) ### Step 4: Analyze the Products - The products of these reactions include carbon monoxide (CO) and potentially hydrogen (H2) if steam is present. - However, when air is mixed with steam and passed over red hot coke, the predominant product is carbon monoxide due to the high temperature and the presence of oxygen. ### Step 5: Identify the Outgoing Gas The outgoing gas from the reaction will primarily be carbon monoxide (CO) along with nitrogen (N2) from the air. This mixture is known as **producer gas**. ### Conclusion The correct answer to the question is that the outgoing gas is **producer gas**, which mainly consists of carbon monoxide and nitrogen. ---
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RESONANCE ENGLISH-P-BLOCK ELEMENT (BORON AND CARBON FAMILY)-Advanced Level Problems Part-I : PRACTICE TEST-1 (IIT-JEE (MAIN Pattern))
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