Cation exchanger zeolite `Na_(12)Al_(12)Si_(17)O_(58).27H_(2)O` can exchange cation with which of the following in aqueous solution ?

Options

A. `Mg(HCO_(3))_(2)`
B. `K_(2)SO_(4)`
C. `CaCl_(2)`
D. `NH_(4)NO_(3)`

Explanation

To determine which cations the zeolite `Na_(12)Al_(12)Si_(17)O_(58).27H_(2)O` can exchange in aqueous solution, we can follow these steps:

### Step 1: Understand the nature of zeolites
Zeolites are aluminosilicate minerals that have a porous structure and can exchange cations. They contain sodium ions (Na+) in their structure, which can be replaced by other cations in solution.

**Hint:** Zeolites are known for their ability to exchange cations due to their porous structure.

### Step 2: Identify the cations in the options
We need to analyze the cations in the given options. The options provided are:
1. Mg(HCO3)2
2. CaCl2
3. NaNH4NO3

**Hint:** Look for cations that can replace Na+ in the zeolite structure.

### Step 3: Determine the solubility of the cations
Cations that are more soluble in water can replace the sodium ions in the zeolite. The cations in the options are:
- From Mg(HCO3)2, the cation is Mg2+.
- From CaCl2, the cation is Ca2+.
- From NaNH4NO3, the cation is NH4+ (ammonium).

**Hint:** Consider the solubility of each cation in water; more soluble cations are likely to exchange with Na+.

### Step 4: Evaluate the exchange potential
- **Mg2+**: Magnesium ions are soluble and can replace Na+.
- **Ca2+**: Calcium ions are also soluble and can replace Na+.
- **NH4+**: Ammonium ions are soluble and can replace Na+.

Since all these cations (Mg2+, Ca2+, and NH4+) are soluble in water, they can effectively exchange with Na+ in the zeolite.

**Hint:** All three cations are soluble in water, making them suitable for cation exchange.

### Step 5: Conclusion
The zeolite `Na_(12)Al_(12)Si_(17)O_(58).27H_(2)O` can exchange cations with:
- Mg(HCO3)2
- CaCl2
- NaNH4NO3

Thus, the correct options are A, B, and C.

**Final Answer:** The zeolite can exchange cations with Mg(HCO3)2, CaCl2, and NaNH4NO3.