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The reactivities of C Cl(4) and SiCl(4) ...

The reactivities of `C Cl_(4)` and `SiCl_(4)` are different. For example `SiCl_(4)` can be easily hydrolysed and is prone to substitution reactions, whereas `C Cl_(4)` is inert.
The observed difference is because
(a)carbon atom has smaller size than hence substitution is not possible
(b)carbon is more electronegative than silicon
( c)silicon has low lying unoccupied orbitals
(d)`C-Cl` bond is stronger than `Si-Cl` bond

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the differing reactivities of \( CCl_4 \) (carbon tetrachloride) and \( SiCl_4 \) (silicon tetrachloride), we can analyze the properties of these compounds and their respective bonds. ### Step-by-Step Solution: 1. **Understanding the Compounds**: - \( CCl_4 \) is carbon tetrachloride, where carbon is bonded to four chlorine atoms. - \( SiCl_4 \) is silicon tetrachloride, where silicon is bonded to four chlorine atoms. 2. **Reactivity Comparison**: - \( SiCl_4 \) is known to undergo hydrolysis and substitution reactions readily. - \( CCl_4 \) is largely inert and does not undergo these reactions. 3. **Analyzing Bond Strength**: - The key difference in reactivity can be attributed to the strength of the \( C-Cl \) bond compared to the \( Si-Cl \) bond. - The \( Si-Cl \) bond is weaker than the \( C-Cl \) bond, making it easier for \( SiCl_4 \) to react with water (hydrolysis) or other nucleophiles (substitution). 4. **Evaluating the Options**: - (a) Carbon atom has a smaller size than silicon, hence substitution is not possible. - This is incorrect; size does not directly influence reactivity in this context. - (b) Carbon is more electronegative than silicon. - While true, electronegativity does not explain the observed reactivity differences. - (c) Silicon has low-lying unoccupied orbitals. - This is not a necessary explanation for the reactivity of \( SiCl_4 \). - (d) \( C-Cl \) bond is stronger than \( Si-Cl \) bond. - This is the correct statement explaining why \( CCl_4 \) is inert while \( SiCl_4 \) is reactive. 5. **Conclusion**: - The observed difference in reactivity between \( CCl_4 \) and \( SiCl_4 \) is primarily due to the strength of the \( C-Cl \) bond being stronger than the \( Si-Cl \) bond, making \( SiCl_4 \) more prone to hydrolysis and substitution reactions. ### Final Answer: The correct answer is (d) \( C-Cl \) bond is stronger than \( Si-Cl \) bond.
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