An organic compound is fused with sodium metal and crushed in water. The solution thus obtained when treated with freshly prepared ferric chloride solution gives blood red color solution. The test confirms

Options

A. Presence of `S` in the organic compound.
B. Presence of `O` in the organic compound
C. Presence of `N` and `O` in the organic compound
D. Presence of `N` and `S` in the organic compound

Explanation

To solve the question step by step, we will analyze the information given and apply our knowledge of chemical reactions and tests.

### Step 1: Understanding the Reaction
The organic compound is fused with sodium metal and then crushed in water. This process typically helps in breaking down the organic compound and releasing ions into the solution.

**Hint:** Think about what happens when organic compounds are treated with sodium metal.

### Step 2: Identifying the Test
The solution obtained from the fusion is treated with freshly prepared ferric chloride (FeCl₃). Ferric chloride is known to react with certain anions to produce characteristic colors.

**Hint:** Recall the specific color changes that occur when ferric chloride reacts with different ions.

### Step 3: Observing the Color Change
The solution gives a blood-red color when treated with ferric chloride. This specific color indicates the presence of thiocyanate ions (SCN⁻).

**Hint:** Remember that blood-red coloration is a key indicator in certain tests, particularly those involving thiocyanate.

### Step 4: The Reaction of Ferric Chloride with Thiocyanate
When ferric chloride reacts with thiocyanate ions, it forms a complex ion, [Fe(SCN)]²⁺, which is responsible for the blood-red color. The reaction can be represented as follows:

\[ \text{Fe}^{3+} + \text{SCN}^- \rightarrow [\text{Fe(SCN)}]^{2+} \]

**Hint:** Consider the stoichiometry of the reaction and the formation of complex ions.

### Step 5: Conclusion
Since the blood-red color indicates the presence of thiocyanate ions, we can conclude that the original organic compound must contain sulfur (S) and nitrogen (N) in its structure, as these elements are necessary to produce thiocyanate ions upon treatment with sodium.

**Hint:** Think about the elements that are typically involved in forming thiocyanate ions.

### Final Answer
The test confirms the presence of sulfur (S) and nitrogen (N) in the organic compound.