Which of the following compound will not react with `I_(2)//OH^(-)`.

Options

A. `CH_(3)-underset(O)underset(||)(C )-CH_(3)`
B. `CH_(3)-underset(OH)underset(||)(CH )-CH_(3)`
C. `CH_(3)-underset(O)underset(||)(C )-Cl`
D. `CH_(3)-CHO`

Explanation

To determine which compound will not react with `I2/OH-`, we need to understand the Iodoform test. This test is used to identify the presence of methyl ketones or compounds that can be oxidized to form methyl ketones. The general structure that gives a positive Iodoform test is CH3C(=O)R, where R can be any alkyl or aryl group.

### Step-by-Step Solution:

1. **Identify the Compounds**: List the compounds given in the question. For this example, let's assume we have four compounds labeled A, B, C, and D.

2. **Check for Methyl Ketone Structure**: For each compound, check if it has the structure CH3C(=O)R or can be oxidized to form such a structure.

- **Compound A**: If it has a structure like CH3C(=O)R, it will react positively.
- **Compound B**: Similarly, check if it can be oxidized to form a methyl ketone.
- **Compound C**: Check for the presence of a methyl group adjacent to a carbonyl group. If there is a highly electronegative group (like Cl) that can destabilize the formation of the methyl ketone, it may not react.
- **Compound D**: If it has a methyl group and can form a methyl ketone, it will react positively.

3. **Analyze Each Compound**:
- **Compound A**: Contains CH3 and can form a methyl ketone. **Reacts**.
- **Compound B**: Contains CH3 and can be oxidized to form a methyl ketone. **Reacts**.
- **Compound C**: Contains a methyl group but has a strong electron-withdrawing group (like Cl) that prevents the formation of the methyl ketone. **Does not react**.
- **Compound D**: Contains a methyl group and can form a methyl ketone. **Reacts**.

4. **Conclusion**: The compound that will not react with `I2/OH-` is **Compound C**.

### Final Answer:
The compound that will not react with `I2/OH-` is **C**.