Yellow precipitate obtained during the test of halogen by lassaigne's test is due to the formation of

Options

A. `AgF`
B. `AgCl`
C. `AgBr`
D. None of these

Explanation

To solve the question regarding the yellow precipitate obtained during the test of halogen by Lassaigne's test, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Lassaigne's Test**:
- Lassaigne's test is a qualitative analysis method used to detect the presence of halogens (like chlorine, bromine, and iodine) in organic compounds.

2. **Reagents Used**:
- In this test, sodium bromide (NaBr) is commonly used as a source of bromine, and silver nitrate (AgNO3) is used as a reagent to test for halogens.

3. **Chemical Reaction**:
- When sodium bromide (NaBr) reacts with silver nitrate (AgNO3), a double displacement reaction occurs. The reaction can be represented as:
\[ \text{NaBr} + \text{AgNO}_3 \rightarrow \text{AgBr} + \text{NaNO}_3 \]

4. **Formation of Yellow Precipitate**:
- The product formed from this reaction is silver bromide (AgBr). Silver bromide is known to form a yellow precipitate when it is produced in the reaction.

5. **Conclusion**:
- Therefore, the yellow precipitate obtained during the test of halogen by Lassaigne's test is due to the formation of silver bromide (AgBr).

### Final Answer:
The yellow precipitate obtained during the test of halogen by Lassaigne's test is due to the formation of **silver bromide (AgBr)**.

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