On oxidative ozonolysis of `3`-Methylhex-`3`-ene, two products `A` & `B` are formed. A gives `CO_(2)` gas with sodium bicarbonate, but `B` can not. The structures of `A` & `B` rae respectively :

Options

A. `CH_(3)-CH_(2)-underset(O)underset(||)(C )-CH_(3)- & CH_(3)-CH_(2)-COOH`
B. `CH_(3)-CH_(2)-COOH & CH_(3)-CH_(2)-CH=O`
C. `CH_(3)-CH_(2)-COOH & CH_(3)-CH-underset(O)underset(||)(C )-CH_(3)`
D. `CH_(3)-CH_(2)-CH_(2)-COOH & CH_(3)-underset(O)underset(||)(C )-CH_(3)`

Explanation

To solve the problem of identifying the products A and B formed from the oxidative ozonolysis of 3-Methylhex-3-ene, we can follow these steps:

### Step 1: Identify the structure of 3-Methylhex-3-ene
3-Methylhex-3-ene is an alkene with a six-carbon chain and a methyl group on the third carbon. The structure can be represented as follows:

```
CH3
|
CH3-CH2-C=CH-CH2-CH3
```

### Step 2: Understand the process of oxidative ozonolysis
In oxidative ozonolysis, the double bond in the alkene is cleaved, and oxygen is added to form carbonyl compounds. The products depend on the nature of the alkene.

### Step 3: Perform ozonolysis on 3-Methylhex-3-ene
When 3-Methylhex-3-ene undergoes ozonolysis, the double bond breaks, leading to the formation of two products:
1. A ketone from the side of the double bond that does not lead to a terminal carbon.
2. An aldehyde that can be further oxidized to a carboxylic acid.

### Step 4: Identify the products
1. **Product A**: The aldehyde formed will be oxidized to a carboxylic acid. The structure of Product A is:
- CH3-CH2-C(=O)OH (which is a carboxylic acid).

2. **Product B**: The ketone formed will remain as a ketone. The structure of Product B is:
- CH3-CH2-C(=O)-CH3 (which is a ketone).

### Step 5: Analyze the reactivity with sodium bicarbonate
- Product A (the carboxylic acid) will react with sodium bicarbonate to produce carbon dioxide (CO2).
- Product B (the ketone) will not react with sodium bicarbonate.

### Conclusion
Thus, the two products formed from the oxidative ozonolysis of 3-Methylhex-3-ene are:
- Product A: Carboxylic acid (CH3-CH2-C(=O)OH)
- Product B: Ketone (CH3-CH2-C(=O)-CH3)

### Final Answer
The structures of A and B are respectively:
- A: CH3-CH2-C(=O)OH (Carboxylic acid)
- B: CH3-CH2-C(=O)-CH3 (Ketone)

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