A rod of length `l` is placed perpendicular to a long wire carrying current `i`. The rod is moved parallel to the wire with a velocity `v`. Find the emf induced in the rod, if its nearest end is at a distance a from the wire.

Explanation

Consider a segment of rod of length `dx`,at a distance `x` from the wire.`Emf` induced in the segment
`dE=(mu_(0)i)/(2pix)dx.v , thereforeE=underset(a)overset(a+l)int(mu_(0)ivdx)/(2pix)=(mu_(0)iv)/(2pi)ln ((l+a)/a)`