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A rod of length l and resistance r rotat...

A rod of length `l` and resistance `r` rotates about one end as shown in figure.Its othr end touches a conducting ring `a` of negligible resistance.`A` resistance `R` is connected between centre and periphery.Draw the electrical equivalence and find the current in the resistance `R`.There is a uniform magnetic field `B` directed as shown.

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current `i=(1/2Bomegal^(2))/(R+r)`
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RESONANCE ENGLISH-ELECTROMAGNETIC INDUCTION-A.l.P
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