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Solve the above question if the length o...

Solve the above question if the length of rod is `2L` and resistance `2r` and it is rotating about its centre.Both ends of the rod now touch the conductiing ring

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`i=epsilon/(R+r/2)=(1/2BomegaL^(2))/(R+r/2)`
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RESONANCE ENGLISH-ELECTROMAGNETIC INDUCTION-A.l.P
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