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Find the mutual inductance of two concen...

Find the mutual inductance of two concentric coils of radii `a_(1)` and `a_(2)(a_(1) lt lt a_(2))` if the planes of the coils are perpendicular.

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To find the mutual inductance of two concentric coils of radii \( a_1 \) and \( a_2 \) (where \( a_1 \ll a_2 \)) with their planes perpendicular, we can follow these steps: ### Step 1: Understand the Setup We have two concentric coils. The inner coil has a radius \( a_1 \) and the outer coil has a radius \( a_2 \). The planes of the coils are perpendicular to each other. ### Step 2: Determine the Magnetic Field When a current \( I \) flows through the outer coil (with radius \( a_2 \)), it generates a magnetic field at the center of the coil. The magnetic field \( B \) at the center of a circular coil is given by the formula: \[ ...
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Find the mutual inductance of two concentric coils of radii a_(1) and a_(2)(a_(1) lt lt a_(2)) if the planes of the coils are same.

Find the mutual inductance of two concentric coils of radii a_(1) and a_(2)(a_(1) lt lt a_(2)) if the planes of the coils are same.

Find the mutual inductance of two concentric coils of radii a_(1) and a_(2)(a_(1) lt lt a_(2)) if the planes of the coils are same.

Find the mutual inductance of two concentric coils of radii a_(1) and a_(2)(a_(1) lt lt a_(2)) if the planes of the coils make an angle theta with each other.

If a_(1)=5 and a_(n)=1+sqrt(a_(n-1)), find a_(3) .

If a_(1)=1, a_(2)=1, and a_(n)=a_(n-1)+a_(n-2) for n ge 3, find the first 7 terms of the sequence.

Let a_(1),a_(2),a_(3),a_(4),a_(5) be a five term geometric sequence satisfies the condition 0 lt a_(1) lt a_(2) lt a_(3) lt a_(4) lt 100 , where each term is an integar . Then the number of five terms in geometric progression are

Find a_(1) and a_(9) if a_(n) is given by a_(n) = (n^(2))/(n+1)

If a_(1) = 2 and a_(n) - a_(n-1) = 2n (n ge 2) , find the value of a_(1) + a_(2) + a_(3)+…+a_(20) .

a_(1), a_(2),a_(3) in R - {0} and a_(1)+ a_(2)cos2x+ a_(3)sin^(2)x=0 " for all " x in R then (a) vectors veca=a_(1) hati+ a_(2) hatj + a_(3) hatk and vecb = 4hati + 2hatj + hatk are perpendicular to each other (b)vectors veca=a_(1) hati+ a_(2) hatj + a_(3) hatk and vecb = hati + hatj + 2hatk are parallel to each each other (c)if vector veca=a_(1) hati+ a_(2) hatj + a_(3) hatk is of length sqrt6 units, then on of the ordered trippplet (a_(1), a_(2),a_(3)) = (1, -1,-2) (d)if 2a_(1) + 3 a_(2) + 6 a_(3) = 26 , " then " |veca hati + a_(2) hatj + a_(3) hatk | is 2sqrt6

RESONANCE ENGLISH-ELECTROMAGNETIC INDUCTION-A.l.P
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