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Two coaxial solenods are made by winding...

Two coaxial solenods are made by winding thin insulated wire over a pipe of cross sectional area A = `10 cm^(2)` and length = 20 cm. If one of the solenoids has 300 turns and the other 400 turns, their mutual inductance is `(mu_(0) = 4pi xx 10^(-7) Tm A^(-1))`

A

`4.8pixx10^(-4)H`

B

`4.8pixx10^(-5)H`

C

`2.4pixx10^(-4)H`

D

`2.4pixx10^(-5)H`

Text Solution

Verified by Experts

The correct Answer is:
C

`M=mu_(0)n_(1)A N_(2) =(4pixx10^(-7))((300)/0.20)(10xx10^(-4))(400)=2.4pixx10^(-4) H`
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