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In a series LCR circuit R = 200 Omega an...

In a series LCR circuit R = 200 `Omega` and the voltage and the frequency on the main supply is 220 V and 50 Hz respectively. On taking out the capacitanc efrom the circuit the current lags behind the voltage by `30^(@)`. On taking out the inductor from the circuit the current leads the voltage by `30^(@)`. The power dissipated in the LCR circuit is

A

`305 W`

B

`210 W`

C

zero `W`

D

`242 W`

Text Solution

Verified by Experts

The correct Answer is:
4

`tan 30^(@)=X_(L)/R rArr X_(L)=R/sqrt3=200/sqrt3,tan 30^(@)=X_(C)/R rArr X_(C)=200/sqrt3`
`Z=sqrt(R+(X_(L)-X_(C))^(2))=200 Omega`.
`i_(rms)=220/200=1.1`
`P=(i_(rms))^(2)xxR=(1.1)^(2)xx200`
`P=242 W`
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