An inductor 200 mH, capactior `500 mu F`, resistor 10 ohm are connected in series with a 100 V, varialbe frequency a.c. source. Calculate (i) frequency at which power factor of the circuit is unity (ii) current amplitude at this frequency (iii) Q factor.

Explanation

To solve the problem step by step, we will break it down into three parts as per the question.

### Given:
- Inductance, \( L = 200 \, \text{mH} = 200 \times 10^{-3} \, \text{H} \)
- Capacitance, \( C = 500 \, \mu\text{F} = 500 \times 10^{-6} \, \text{F} \)
- Resistance, \( R = 10 \, \Omega \)
- Voltage, \( V = 100 \, \text{V} \)

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