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The angle made by the string of a simple...

The angle made by the string of a simple pendulum with the vertical depends on time as `theta=pi/90sin[(pis^-1)t]`. Find the length of the pendulum if `g=pi^2ms^-2`

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The correct Answer is:
`0.25 m`
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RESONANCE ENGLISH-SIMPLE HARMONIC MOTION -Exercise- 1, PART - I
  1. The angle made by the string of a simple pendulum with the vertical de...

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  2. The equation of a particle executing SHM is x = (5m)sin[(pis^(-1))t + ...

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  3. A particle having mass 10 g oscilltes according to the equatioi (x=(2....

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  4. A simple harmonic motion has an amplitude A and time period T. Find th...

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  5. At particle is executing SHM with amplitude A and has maximum velocity...

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  6. A particle executes simple harmonic motion with an amplitude of 10 cm ...

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  7. A particle is executing SHM. Find the positions of the particle where ...

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  8. A particle performing SHM with amplitude 10cm. At What distance from m...

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  9. An object of mass 0.2 kg executes simple harmonic oscillation along th...

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  10. A spring mass system has time period of 2 second. What should be the s...

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  11. A body of mass 2 kg suspended through a vertical spring executes simpl...

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  12. A vertical spring-mass system with lower end of spring is fixed, made ...

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  13. The spring shown in figure is unstretched when a man starts pulling on...

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  14. Three spring mass systems are shown in figure. Assuming gravity free s...

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  15. Spring mass system is shown in figure. find the time period of vertica...

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  16. Find the length of seconds pendulum at a place where g =4 pi^(2) m//s^...

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  17. The angle made by the string of a simple pendulum with the vertical de...

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  18. A pendulum clock giving correct time at a place where g=9.800 ms^-2 is...

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  19. A pendulum is suspended in a lit and its period of oscillation is T(0)...

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  20. Compound pendulum are made of A rod of length l suspended through a p...

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  21. A uniform disc of mass m and radius r is suspended through a wire atta...

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