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A particle simultaneously participates in two mutually perpendicular oscillations `x = sin pi t` & `y = 2cos 2 pit`. Write the equation of trajectory of the particle.

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The correct Answer is:
`2x^(2) + (y)/(2) = 1`

`x = sinpit, y = 2 [1 - 2 sin^(2) pit]`
`y = 2[1 - 2x^(2)]` or `2x^(2) + (y)/(2) = 1` Ans
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