Find the acceleration of the 500 g block in figure.

Options

A. `pisqrt((m)/(2k)) + (2L)/(v)`
B. `pisqrt((m)/(2k)) + (L)/(v)`
C. `pisqrt((m)/(2k)) - (L)/(v)`
D. `pisqrt((m)/(k)) + (L)/(v)`

Answer

A

Explanation

since all collision are elestic and total energy is conserved
Time period of motion of right block is `t_(1) = (2L)/(v)`.
Time period of motion of left block is `t_(2) = (1)/(2)2pisqrt((m)/(2k))`
So. Total time period `= (2L)/(v) + (1)/(2) [2pisqrt((m)/(2k))]`