A uniform rope of elngth `l` and mass `m` hangs vertically from a rigid support. A block of mass `m` is attached to the free end of the rope. A transverse pulse of wavelength `lambda` is produced at the lower end of the rope. The wavelength of the pulse, when it reaches the top of the rope. is `alambda`. Find `a^(2)`

Answer

2

Explanation

`f = ((f)/(lambda))` at lowest point
`f = (1)/(lambda)sqrt((mg)/(mu))`
`f^(1) = (v^(1))/(lambda^(1))` at highest point
`f^(1) = (1)/(lambda^(1)) sqrt(((M + m)g)/(mu))`
`f^(1) = f :` no any change in source frq.
`(1)/(lambda) sqrt((mg)/(mu)) = (1)/(lambda), sqrt(((M + m)g)/(mu)) rArr [lambda' = lambdasqrt((M + m)/(m))]`