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A thermally isolated vessel contains 100...

A thermally isolated vessel contains `100g` of water at `0^(@)C`. When air above the water is pumped out, some of the water freezes and some evaporates at `0^(@)C` itself. Calculate the mass of the ice formed such that no water is left in the vessel. Latent heat of vaporization of water at `0^(@)C=2.10xx10^(6)J//kg` and latent heat of fusion of ice `=3.36xx10^(5)J//kg`.

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To solve the problem step by step, we will use the principles of thermodynamics, particularly the concept of conservation of energy in a thermally isolated system. ### Step 1: Understand the system We have a thermally isolated vessel containing 100 g of water at 0°C. When air is pumped out, some water freezes and some evaporates. Our goal is to find the mass of ice formed such that no water is left in the vessel. ### Step 2: Define variables Let: - \( y \) = mass of ice formed (in kg) ...
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A thermally isolated vessel contains 100 g of water at 0^(@)C when air above the water is pumped out, some of the water freezes and some evaporates at 0^(@)C itself. Calculate the mass at 0^(@)C=2.10xx10^(6) j//kg and latent heat of fusion of ice =3.36xx10^(5) j//kg .

A thermally insulated vessel contains 150g of water at 0^(@)C . Then the air from the vessel is pumped out adiabatically. A fraction of water turms into ice and the rest evaporates at 0^(@)C itself. The mass of evaporated water will be closest to : (Latent heat of vaporization of water =2.10xx10^(6)jkg^(-1) and Latent heat of Fusion of water =3.36xx10^(5)jkg^(-1) )

A thermal insulated vessel contains some water at 0^(@)C . The vessel is connected to a vaccum pump to pum out water vapour. This results in some water getting frozen. It is given latent heat of vaporization of water at 0^(@)C = 21 xx 10^(5) J//kg and latent heat of freezing of water =3.36 xx 10^(5) J//kg . the maximum percentage amount of water vapour that will be solidified in this manner will be:

A piece of ice of mass 40 g is added to 200 g of water at 50^@ C. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water = 4200 J kg^(-1) K^(-1) and specific latent heat of fusion of ice = 336 xx 10^3" J "kg^(-1) .

1kg ice at 0^(@)C is mixed with 1kg of steam at 100^(@)C . What will be the composition of the system when thermal equilibrium is reached ? Latent heat of fusion of ice = 3.36xx 10^(6)J kg^(-1) and latent heat of vaporization of water = 2.26 xx 10^(6)J kg^(-1)

If 10 g of ice is added to 40 g of water at 15^(@)C , then the temperature of the mixture is (specific heat of water = 4.2 xx 10^(3) j kg^(-1) K^(-1) , Latent heat of fusion of ice = 3.36 xx 10^(5) j kg^(-1) )

How should 1 kg of water at 50^(@)C be divided in two parts such that if one part is turned into ice at 0^(@)C . It would release sufficient amount of heat to vapourize the other part. Given that latent heat of fusion of ice is 3.36xx10^(5) J//Kg . Latent heat of vapurization of water is 22.5xx10^(5) J//kg and specific heat of water is 4200 J//kg K .

The specific latent heat of fusion of ice is 336 xx 10^3 J/kg. What does this statement mean?

Some water at 0^@C is placed in a large insulated enclosure (vessel). The water vapour formed is puped out continuously. What fraction of the water will ultimately freeze, if the latent heat of vapourization is seven times the latent heat of fusion?

A piece of ice of mass of 100g and at temperature 0^(@)C is put in 200g of water of 25^(@) How much ice will melt as the temperature of the water reaches 0^(@)C ? The specific heat capacity of water = 4200 J kg ^(-1)K^(-1) and the latent heat of ice = 3.36 xx 10^(5)J kg^(-1)

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