For `Ag, bar(C)_(p)(JK^(-1)mol^(-1))` is given by `24+0.006 T`. Calculate `Delta H` if `3 mol` of silver are raised from `27^(@)C` to its melting point `927^(@)C` under `1 atm` pressure.

Explanation

To calculate the change in enthalpy (ΔH) for raising the temperature of 3 moles of silver (Ag) from 27°C to its melting point at 927°C, we will use the given heat capacity function \( C_p(T) = 24 + 0.006T \) (in J/K·mol).

### Step-by-Step Solution:

1. **Convert Temperatures to Kelvin:**
- Initial temperature, \( T_1 = 27°C = 27 + 273 = 300 K \)
- Final temperature, \( T_2 = 927°C = 927 + 273 = 1200 K \)

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