Calculate the amount of heat evolved during the complete combustion of `100 ml` of liquid benzene from the following data. Predict your answer as `(Delta H)/(100)` ( in KJ/mol).
(i) `18 gm` of graphite on complete combustion evolve 585 KJ heat
(ii) 15540 KJ heat is required to dissociate all the molecules of 1 litre water into `H_(2)` and `O_(2)`.
(iii) The heat of formation of liquid benzene is 48 kJ/mol
(iv) Density of `C_(6)H_(6)(l)=0.87 gm//ml`

Explanation

(i) `C(s)+O_(2)(g)rarrCO_(2)(g), DeltaH_(f)^(@)= -393.33 KJ//mol`
(ii) `H_(2)(g)+(1)/(2)O_(2)(g)rarrH_(2)O(l), Delta H_(f)^(@)= -286 KJ//mol`
(iii) `C_(6)H_(6)(l)+(15)/(2)O_(2)(g)rarr6CO_(2)(g)+3H_(2)O(l)`
`:. DeltaH^(@)=[6(-393.33)+3(-286)]-50=-3268 KJ//"mole"`
`:.` Heat evolved from `87 g` benzene `3645 KJ`