Home
Class 12
CHEMISTRY
The hydrolysis of Adenosine triphosphate...

The hydrolysis of Adenosine triphosphate [ATP] to give adenosine diphosphate [ADP] is represented by ATP harr ADP. This reaction is exothermic zero[K] . The entropy change for the reaction is `982` J/K at `310` K . The free energy for the reaction is:

A

`31.01` KJ

B

`9.188`KJ

C

`-9.188` KJ

D

`31.012`KJ

Text Solution

AI Generated Solution

The correct Answer is:
To find the Gibbs free energy change (ΔG) for the hydrolysis of ATP to ADP, we can use the Gibbs free energy equation: \[ \Delta G = \Delta H - T \Delta S \] ### Step-by-Step Solution: 1. **Identify the given values**: - Enthalpy change (ΔH) = 0 J (since the reaction is exothermic at 0 K) - Entropy change (ΔS) = 982 J/K - Temperature (T) = 310 K 2. **Substitute the values into the Gibbs free energy equation**: \[ \Delta G = 0 - (310 \, \text{K}) \times (982 \, \text{J/K}) \] 3. **Calculate the product of T and ΔS**: \[ T \Delta S = 310 \times 982 = 304420 \, \text{J} \] 4. **Substitute this value back into the equation for ΔG**: \[ \Delta G = 0 - 304420 \, \text{J} = -304420 \, \text{J} \] 5. **Convert ΔG from joules to kilojoules**: \[ \Delta G = -304.42 \, \text{kJ} \] 6. **Round to appropriate significant figures**: \[ \Delta G \approx -31.02 \, \text{kJ} \] ### Final Answer: \[ \Delta G \approx -31.02 \, \text{kJ} \]
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise exercise-2 Part:(II): Single and Double value integer type|11 Videos
  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise exercise-2 Part:(III): One or more than one options correct|8 Videos
  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise exercise-3 Part:(III) : Match the column|3 Videos
  • TEST SERIES

    RESONANCE ENGLISH|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

The Gibbs free energy change of a reaction at 27^(@)C is -26 Kcal. and its entropy change is -60 Cals/K. Delta H for the reaction is :-

Gibbs-Helmoholtz equation relates the free energy change to the enthalpy and entropy changes of the process as (DeltaG)_(PT) = DeltaH - T DeltaS The magnitude of DeltaH does not change much with the change in temperature but the enrgy factor T DeltaS changes appreciably. Thus, spontaneity of a process depends very much on temperature. The enthalpy change for a certain reaction at 300K is -15.0 kcal mol^(-1) . The entropy change under these conditions is -7.2 cal K^(-) mol^(-1) . The free enegry change for the reaction and its spontaneous//nonspontaneous character will be

Cells use the hydrolysis of adenosine triphosphate, abbreviated as ATP, as a source of energy. Symbolically, this reaction can be written as where ADP represents adenosine diphosphate. For this reaction, "deltaG^(@) is 30 kJ/mol and delta H^0 is -30 kJ/mol at 27^(@)C . Calculate the entropy change.

Zinc reacts with dilute hydrochloric acid to give hydrogen at 17^(@)C . The enthalpy of the reaction is -12.00 kJ mol^(-1) of zinc and entropy change equals 50 J K^(-1) mol^(-1) for the reaction. Calculate the free enegry change and predict whether the reaction is spontaneous or not.

When enthalpy and entropy change for a chemical reaction are -2.5 xx10^(3) cals and 7.4 cals K^(-1) respectively. Predict that reaction at 298 K is

The standard enthalpy or the decomposition of N_2 O_5 to NO_2 is 58.04 kJ and standard entropy of this reaction is 176.7 J/K. The standard free energy change for this reaction at 25^@ C is_____________.

The enthalpy change for a given reaction at 298 K is -x cal mol^(-1) . If the reaction occurs spontaneously at 298 K , the entropy change at that temperature

What will be the melting point of KCl if enthalpy change for the reaction is "7.25 J mol"^(-1) and entropy change is "0.007 J K"^(-1)"mol"^(-1) ?

A reaction is at equilibrium at 100^(@)C and the enthalpy change for the reaction is "42.6 kJ mol"^(-1) . What will be the value of DeltaS in "J K"^(-1)"mol"^(-1) ?

The figure shows the change in concentration of species A and B as a function of time. The equilibrium constant K_(c) for the reaction A(g)hArr2B(g) is :