Calculate the potential of hydrogen electrode in contact with a solution whose pH is 10.

Explanation

Given: `Ph=10`
Asked (a) `E_(H^(+)//H_(2))=?`
(b). `E_(cell)^(0)=?`
formula used: (a). `E_(el)=E_(el)^(@)-(0.0591)/(n)log((["product"])/(["reactant"]))`
Explanation: `E_(el)=E_(el)=` electrode potential of single electrode
`E_(el)^(@)=` Standard electrode potential of single electrode.
Substitutio and calculation:
`Ph=10implies[H^(+)]=10^(-10)molL^(-1)`
`E_(H^(+)//H_(2))=E_(H^(+)//H_(2))-(0.0591)/(1)log((1)/([H^(+)])`
`=0-(0.0591)/(1)log((1)/(10^(-10))=E_(H^(+)//H_(2))=-0.591V`